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1¡¢HPO42-µÄ¹²éî¼îÊÇ( C )
A¡¢H2PO4- B¡¢H3PO4 C¡¢ PO43- D¡¢ OH- 2¡¢ÏÂÁÐÈÜÒºÓÃËá¼îµÎ¶¨·¨ÄÜ׼ȷµÎ¶¨µÄÊÇ( A )
A¡¢0.1 mol/L HF (pKa = 3.18) B¡¢ 0.1 mol/L HCN (pKa = 9.21) C¡¢0.1 mol/L NaAc [pKa(HAc) = 4.74] D¡¢ 0.1 mol/L NH4Cl
[pKb(NH3) = 4.75]
3¡¢ÔÚË®ÈÜÒºÖй²éîËá¼î¶ÔKaÓëKbµÄ¹ØÏµÊÇ ( B )
A¡¢ Ka¡¤Kb=1 B¡¢ Ka¡¤Kb=Kw C¡¢ Ka/Kb=Kw D¡¢ Kb/Ka=Kw 4¡¢Å¨¶ÈÏàͬµÄÏÂÁÐÎïÖÊË®ÈÜÒºµÄpH×î¸ßµÄÊÇ D )
A¡¢ NaCl B¡¢ NaHCO3 C¡¢ NH4Cl D¡¢ Na2CO3 5¡¢ÏÂÁÐÑεÄË®ÈÜÒº»º³å×÷ÓÃ×îÇ¿µÄÊÇ ( C )
A¡¢ NaAc B¡¢ Na2CO3 C¡¢ Na2B4O7¡¤10H2O D¡¢ Na2HPO4 6¡¢Ç¿ËáµÎ¶¨Èõ¼î,ÒÔÏÂָʾ¼ÁÖв»ÊÊÓõÄÊÇ------( C )
A¡¢ ¼×»ù³È B¡¢ ¼×»ùºì C¡¢ ·Ó̪ D¡¢ äå·ÓÀ¶ (pT = 4.0) 7¡¢ÓÃ0.1 mol/L HClµÎ¶¨0.1 mol/L NaOHµÄͻԾ·¶Î§Îª9.7~4.3, Ôò0.01 mol/L HClµÎ¶¨0.01 mol/L NaOHµÄͻԾ·¶Î§Ó¦Îª--( C )
A¡¢ 9.7~4.3 B¡¢ 8.7~4.3 C¡¢8.7~6.3 D¡¢ 10.7~3.3
8¡¢ 0.20mol/L HClÓë0.30mol/L Na2CO3ÈÜÒºµÈÌå»ý»ìºÏ,¸ÃÈÜÒºµÄpHΪ£¨ A £©¡£ (H2CO3µÄpKa1 = 6.38, pKa2 = 10.25)
A¡¢9.95 B¡¢4.05 C¡¢10.25 D¡¢10.55
9¡¢½ñÓûÓÃH3PO4ÓëNa2HPO4À´ÅäÖÆpH = 7.2µÄ»º³åÈÜÒº£¬ÔòH3PO4ÓëNa2HPO4ÎïÖʵÄÁ¿Ö®±Èn(H3PO4)¡Ãn(Na2HPO4)Ó¦µ±ÊÇ( C ) (H3PO4µÄpKa1~pKa3·Ö±ðÊÇ2.12,7.20,12.36) A¡¢ 1:1
B¡¢1:2 C¡¢ 1:3
D¡¢ 3:1
10¡¢Îª±ê¶¨HClÈÜÒº¿ÉÒÔÑ¡ÔñµÄ»ù×¼ÎïÊÇ ( B )
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A¡¢ NaOH B¡¢ Na2CO3 C¡¢ Na2SO3 D¡¢ Na2S2O3
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1¡¢ÏÂÁи÷×é×é·ÖÖв»ÊôÓÚ¹²éîËá¼î¶ÔµÄÊÇ ( A )
A¡¢ H2CO3ºÍCO32- B¡¢ NH3ºÍNH2- C¡¢HClºÍCl- D¡¢ HSO4- ºÍSO42- 2¡¢ÏàͬŨ¶ÈµÄCO32-¡¢S2-¡¢C2O42-ÈýÖÖ¼îÐÔÎïÖÊË®ÈÜÒº, Æä¼îÐÔÇ¿Èõ(ÓÉ´óÖÁС)µÄ˳ÐòÊÇ ( C)
(ÒÑÖª H2CO3£ºpKa1 = 6.38£¬ pKa2 = 10.25£»H2S£ºpKa1 = 6.88 £¬pKa2 = 14.15£»H2C2O4£ºpKa1 = 1.22£¬pKa2 = 4.19 )
A¡¢CO32->S2->C2O42- B¡¢ S2->C2O42->CO32- C¡¢S2->CO32->C2O42- D¡¢ C2O42->S2->CO32-
3¡¢.¼Ó 40 mL 0.15mol/L HClÈÜÒºÖÁ60mL 0.10mol/L Na2CO3ÈÜÒºÖÐ,¸ÃÈÜÒºµÄºÏÀíµÄ¼ò»¯ÖÊ×ÓÌõ¼þÊÇ£¨B £©
A¡¢[H2PO4£]=[HPO42-] B¡¢[H3PO4]=[HPO42-] C¡¢[PO43£]=[HPO42-] D¡¢ [H3PO4]=[H2PO4-]
4¡¢ÒÔ¼×»ùºìΪָʾ¼Á,ÄÜÓÃNaOH±ê×¼ÈÜҺ׼ȷµÎ¶¨µÄËáÊÇ( B ) A¡¢ ¼×Ëá B¡¢ ÁòËá C¡¢ ÒÒËá D¡¢ ²ÝËá
5¡¢½ñÓûÓÃH3PO4ÓëNaOHÀ´ÅäÖÆpH = 7.20µÄ»º³åÈÜÒº,ÔòH3PO4ÓëNaOHÎïÖʵÄÁ¿Ö®±È n(H3PO4)¡Ãn(NaOH)Ó¦µ±ÊÇ ( D ) (H3PO4µÄpKa1~pKa3·Ö±ðÊÇ2.12,7.20,12.36) A¡¢ 1:1
B¡¢ 1:2
C¡¢ 2:1 D¡¢ 2:3
6¡¢ ÓÃNaOH±ê×¼ÈÜÒºµÎ¶¨0.1mol/LHCl-0.1mol/L H3PO4»ìºÏÒº,Ôڵζ¨ÇúÏßÉϳöÏÖ¼¸¸öͻԾ---( B )
A¡¢1 B¡¢2 C¡¢3 D¡¢ 4
7¡¢ÒÑÖª0.10 mol¡¤L-1 Ò»ÔªÈõËᣨHB£©ÈÜÒºµÄPH=3.0£»0.10 mol¡¤L-1¸ÃËáµÄ¹²éî¼îNaBµÄPHÊÇ(A)
A¡¢11 B¡¢9.0 C¡¢8.5 D¡¢9.5 8¡¢NaHCO3ÔÚË®ÈÜÒºÖеÄÖÊ×ÓÌõ¼þʽΪ£º(B)
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A¡¢[H+] + [H2CO3] = [CO32-] + [OH-] B¡¢[H+] + 2[H2CO3] = [CO32-] + [OH-] C¡¢[H+] = [CO32-] + [OH-]
D¡¢[H+] + [HCO3- ] = [CO32-] + [OH-] + [H2CO3]
9¡¢ÓÃ0.1 mol/L HClµÎ¶¨0.1 mol/L NH3Ë®(pKb = 4.7)µÄpHͻԾ·¶Î§Îª6.3~4.3, ÈôÓÃ0.1 mol/L HClµÎ¶¨0.1 mol/L pKb = 2.7µÄij¼î, pHͻԾ·¶Î§Îª( C ) A¡¢ 6.3~2.3 B¡¢8.3~2.3 C¡¢8.3~4.3 D¡¢4.3~6.3 10¡¢ÏÂÁи÷×éËá¼î¶ÔÖУ¬ÊôÓÚ¹²éîËá¼î¶ÔµÄÊÇ(B) A¡¢ H2CO3----CO32- B¡¢ H3+O----OH-
C¡¢ HPO42- ----PO43- D¡¢ NH3+CH2COOH----NH2CH2COO-
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1£®ÒÑ֪ijËáKa=10-5£¬Æä¹²éî¼îµÄpKb=£¨ 9 £©¡£
2£®ÓÃ0.100mol L-1HClÈÜÒºµÎ¶¨Í¬Å¨¶ÈNaOHÈÜÒº£¬ÆäpHͻԾ·¶Î§ÊÇ9.7~4.3£¬ÈôHCl ºÍNaOHÈÜҺŨ¶È¾ù¼õС10±¶£¬ÔòpHͻԾ·¶Î§ÊÇ£¨ 8.7~5.3 £©¡£
3£®¸ù¾ÝËá¼îÖÊ×ÓÀíÂÛOHµÄ¹²éîËáÊÇ£¨ H2O £©£»HOAcµÄ¹²éî¼îÊÇ£¨ OAc- £©¡£
4£®H2C2O4µÄpKa1=1.2 £¬pKa2= 4.2 £¬µ±PH=1.2ʱ²ÝËáÈÜÒºÖеÄÖ÷Òª´æÔÚÐÎʽÊÇ£¨ H2C2O4 £©ºÍ£¨ HCO4- £©£»µ±HC2O4 - ´ïµ½×î´óֵʱpH=£¨ £©¡£
5£®ÈÜÒºÖÐËá¼îָʾ¼ÁµÄÑÕÉ«ÊÇÓɹ²éîËá¼î¶ÔµÄ£¨ ±È £©Öµ¾ö¶¨µÄ¡£Ëá¼îָʾ¼ÁµÄÀíÂÛ±äÉ«·¶Î§ÊÇ£¨ PH=PKa¡À1 £©£¬ÀíÂÛ±äÉ«µãΪ£¨ PH=PKa £©¡£
6£®Ëá¼îµÎ¶¨Ê±£¬Ëᣨ¼î£©µÄKa£¨Kb£©ÖµÔ½£¨ ´ó £©£¬Ëᣨ¼î£©µÄŨ¶ÈÔ½£¨ ¸ß £©£¬ÆäpHͻԾ·¶Î§Ô½´ó¡£
7£®¼×»ù³Èָʾ¼ÁµÄËáʽ½á¹¹Îª£¨ ºì £©É«£¬¼îʽ½á¹¹Îª£¨ »Æ £©É«¡£
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