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}
习题4 1: 0 2: 20
3: (x<30&&x>20)||(x<-100) 4: ***a=25,b=14,c=16*** 5: 37 6: if(a<=b) printf(\ else printf(\ 7、
#include
#include
m=(y-2)*(y-2); if((m+n)<=1) printf(\ else printf(\ getch(); } 10、
#include
switch(a/10) { case 5:m=4;break; case 4:m=3;break; case 3:m=2;break; case 2:m=1;break; default:m=5; } 12、
方法一:
#include
printf(\ getch(); }
方法二:
#include
方法三:
#include
习题5
1、void main() { int n,value; int i,count=0; float average = 0; long int sum = 0; scanf(\ for(i = 0; i < n; i++)
{ scanf(\ if(value%2 == 0) { sum+=value; count++; } } average = sum / (float)count; printf(\ } 2、
#include \ void main() { char ch; int zm = 0, sz = 0; ch = getchar(); while(ch != '*') { if((ch >= 'A' && ch <= 'Z') || (ch >= 'a' && ch < 'z') ) zm++; if(ch >= '0' && ch <= '9') sz++; ch = getchar(); } printf(\ } 3、
void main() { long i_value; int sum = 0; int temp = 0; scanf(\ if(i_value < 0) {printf(\error!\\n\ for(;;) { temp = i_value;
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