《质量管理学》课程综合练习题

16141210864201234567

28. 解： xmax= 23 xmin= 10 R= 23-10 = 13 取 k = 7 h = 13/7 ≈ 2 组号 1 2 3 4 5 9.5- 11.5- 13.5- 15.5- 17.5- 组界 11.5 13.5 15.5 17.5 19.5 频数 3 6 14 16 7 （手绘作图） 6 19.5- 21.5 2 7 21.5- 23.5 2

29. 解：Rs = CL= X =

?Rs = 170/9 = 18.89

N?11n?X= 871/10 =87.1

UCL= X+ E2Rs = 87.1 +2.66×18.89 = 137.34 LCL= X- E2Rs = 87.1- 2.66×18.89 = 36.86

CLR= Rs = 18.89

UCLR= D4Rs = 3.267×18.89= 67.71 LCLR= D3Rs = 0×18.89= 0

轮廓线： UCL = 137.34

CL = 87.1 LCL= 36.86

UCLR= 67.71 CLR= 18.89 LCLR=0

30. 解：（计算表） N 1 2 3 4 5 6 7 X(路分) 312 383 405 300 371 356 366 RS - 71 22 105 71 15 10 Rs?Rs = = 399/9 = 44.33

N?1 CL= X =

8 343 23 9 390 47 10 355 35 1n?X= 3581/10 =358.1

UCL= X+ E2Rs = 358.1 +2.66×44.33 = 476.03 LCL= X- E2Rs = 358.1- 2.66×44.33 =240.17 CLR= Rs = 44.33

UCLR= D4Rs = 3.267×44.33= 144.84 LCLR= D3Rs = 0×44.33= 0

轮廓线： UCL = 476.03

CL = 358.1 LCL= 240.17

UCLR= 144.84 CLR= 44.33 LCLR=0

31. 解：(计算表) 日期1 趟次 1 2.5 2 2.1 3 2.2 4 2.4 X 2 1.8 2.3 2.1 2.2 2.1 0.5 3 2.3 2.2 1.8 2.1 2.1 0.5 4 2.1 2.4 2.3 1.8 2.15 0.6 5 1.9 2.0 1.9 2.2 2 0.3 6 2.0 1.9 2.4 2.3 2.15 0.5 7 1.8 2.1 2.3 2.2 2.1 0.5 8 2.3 2.1 1.8 2.2 2.1 0.5 2.3 0.4 1nR CL=X=

?X=17/8 =2.125

CLR= R = 3.8/8=0.475 UCL= X+A2R= 2.125 +0.729×0.475≈ 2.47 LCL= X-A2R = 2.125 -0.729×0.475≈1.78 UCLR= D4R = 2.282×0.475 ≈ 1.08 LCLR= D3R = 0×0.47 = 0 轮廓线： UCL = 2.47

CL = 2.125 LCL= 1.78

UCLR= 1.08 CLR=0.475 LCLR=0

32. 解：（计算表） 观测值 组号 X1 X2 X3 X4 1 3.0 4.2 3.5 3.8 2 4.3 4.1 3.7 3.9 3 4.2 3.6 3.2 3.4 4 3.9 4.3 4.0 3.6 5 4.4 3.4 3.8 3.9 6 3.9 4.5 4.3 3.6 7 3.8 3.9 4.3 4.5 8 4.4 4.3 3.8 3.9 9 3.7 3.2 3.4 4.2 10 3.1 3.9 4.2 3.0 X R 1.2 0.6 1.0 0.7 1.0 0.9 0.7 0.6 1.0 1.2 3.62 4.0 3.60 3.95 3.88 4.08 4.12 4.10 3.62 3.50 R = 8.9/10 = 0.89

CL=X=

1n?X=38.5/10 =3.85

UCL= X+A2R= 3.85 +0.729×0.89= 4.5 LCL= X-A2R = 3.85 -0.729×0.89 =3.2 CLR= R = 0.89

UCLR= D4R = 2.282×0.89 = 2.03 LCLR= D3R = 0×0.89 = 0 轮廓线： UCL = 4.5

CL = 3.85 LCL= 3.2

UCLR= 2.03 CLR= 0.89 LCLR= 0 33. 解：R= 3/6 = 0.5

~ CL= X = 2

~ UCL= X+m3 A2R= 2 +0.691×0.5 = 2.35 ~ LCL= X- m3 A2R= 2 -0.691×0.5 =1.65 CLR=R= 0.5

UCLR= D4R=2.115×0.5 = 1.06 LCLR= D3R=0×0.5 = 0

轮廓线： UCL = 2.35

CL = 2 LCL= 1.65

UCLR= 1.06 CLR= 0.5 LCLR= 0