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ǰλãҳ > 工程力学(静力学与材料力学)课后习题答案 - 百度文库

工程力学(静力学与材料力学)课后习题答案 - 百度文库

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  • 2025/6/22 20:22:45

(2) ѡϵAxyгƽ̣ⷽ

?F?MAx?0: ?FAx?0.4?0 FAx?0.4 kN

(F)?0: ?2?0.8?0.5?1.6?0.4?0.7?FB?2?0 FB?0.26 kN

?FԼķͼʾ

y?0: FAy?2?0.5?FB?0 FAy?1.24 kN

(c)(1) оABˣͼ(ƽϵ)

(2) ѡϵAxyгƽ̣ⷽ

FAx FA y 1 y A M=3 C q =2 2?dx B x

dx 2 x 30o FB ?MB(F)?0: ?FAy?3?3??2?dx?x?002

FAy?0.33 kN?Fy?0: FAy??2?dx?FBcos30o?002

FB?4.24 kN?FԼķͼʾ

x?0: FAx?FBsin30o?0 FAx?2.12 kN

(e)(1) оCABDˣͼ(ƽϵ)

q=20 C dx 20?dx y FAx A x FA y M=8 B FB 20 D x

0.8 0.8 0.8 0.8

(2) ѡϵAxyгƽ̣ⷽ

?Fx?0: FAx?0

17 ҳ/ 80ҳ

?MA(F)?0: ?20?dx?x?8?FB?1.6?20?2.4?000.8

FB?21 kN?Fy?0: ??20?dx?FAy?FB?20?000.8

FAy?15 kNԼķͼʾ

4-5 ABһǽڣɶװлٵDΪG

ABΪbбǦ߳?ǣ̶˵Լ

⣺(1) оAB()ͼ(ƽϵ)

FAx MA A FA y (2) ѡϵBxyгƽ̣ⷽ

G B x

b y A b B ?D ?G ?F?Fyx?0: -FAx?Gsin??0 FAx?Gsin? FAy?G(1?cos?)

?0: FAy?G?Gcos??0

?MB(F)?0: MA?FAy?b?G?R?G?R?0 MA?G(1?cos?)bԼķͼʾ

18 ҳ/ 80ҳ

4-7 ¯ϻܳAͿƶBɡܳϵĹ˶ּ

Ϊ2 mܳܡƽOCԼ϶C϶ÿװW=15 kNƽ۳OC=5 mܳADиΪPڲܵߣPӦʹ϶ʱܳ·

D P C O 5m 1m 1m E A F B W ⣺(1) оܳܡƽOCԼ϶Cͼ(ƽƽϵ)

O (2) ѡFΪģгƽ̣ⷽ

E FE D 1m 1m A F FF P C

5m W ?M(3)

F(F)?0: -FE?2?P?1?W?4?0

P FE??2W2FE?0?P?4W?60 kN

4-13 ڹ⻬ˮƽϣǦڣACABΪQ

A㣬˴ýADEӡһΪPFDEBCԼ

B h l D P a E A l ??C 19 ҳ/ 80ҳ

⣺(1)о壬ͼ(ƽƽϵ)

B D h A y l P Q Q a E x

FB (2) ѡϵBxyгƽ̣ⷽ

FC C l ???Ml3l(F)?0: -Q?cos??Q?cos??P??2l?a?cos??FC?2lcos??0B22a?? FC?Q??1??P?2l??Fy?0: FB?FC?2Q?P?0

a FB?Q?P2l(3) оABͼ(ƽϵ) FA y A

FAx h l

Q FD D ?

B FB

(4) ѡAΪģгƽ̣ⷽ

?Ml(F)?0: -F?lcos??Q?cos??FD?h?0AB2

a?lcos?? FD??Q?P?l?2h?4-15 ڳϻиܸAB=500 mmAC=100 mmܵˮƽFQá

֪Q=5000 NزƣƶʱڵBFǶ٣

C F 20 ҳ/ 80ҳ

15o A D 45o FQ B

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(2) ѡϵAxyгƽ̣ⷽ ?F?MAx?0: ?FAx?0.4?0 FAx?0.4 kN (F)?0: ?2?0.8?0.5?1.6?0.4?0.7?FB?2?0 FB?0.26 kN ?FԼķͼʾ y?0: FAy?2?0.5?FB?0 FAy?1.24 kN (c)(1) оABˣͼ(ƽϵ) (2) ѡϵAxyгƽ̣ⷽ FAx FA y 1 y A M=3 C q =2 2?dx B x dx 2 x 30o

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