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2014中考数学专题复习 - 压轴题(含答案)

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  • 2025/5/25 19:21:39

(注:正确画出1个图得2分,无作图痕迹或痕迹不正确不得分) (2)若三角形为锐角三角形,则其最小覆盖圆为其外接圆; ·································· 6分

若三角形为直角或钝角三角形,则其最小覆盖圆是以三角形最长边(直角或钝角所对的边)为直径的圆. ·················································································································· 8分

(3)此中转站应建在△EFH的外接圆圆心处(线段EF的垂直平分线与线段EH的垂直平分线的交点处). ·········································································· 10分 理由如下:

由?HEF??HEG??GEF?47.8??35.1??82.9?,

?EHF?50.0?,?EFH?47.1?,

故△EFH是锐角三角形,

所以其最小覆盖圆为△EFH的外接圆,

设此外接圆为?O,直线EG与?O交于点E,M, 则?EMF??EHF?50.0??53.8???EGF.

故点G在?O内,从而?O也是四边形EFGH的最小覆盖圆.所以中转站建在△EFH的外接圆圆心处,能够符合题中要求. ············································································ 12分

G M H 32.4? 49.8?53.8 ? 50.0? 44.0? 47.1? F

47.8?35.1 ? E

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(注:正确画出1个图得2分,无作图痕迹或痕迹不正确不得分) (2)若三角形为锐角三角形,则其最小覆盖圆为其外接圆; ·································· 6分 若三角形为直角或钝角三角形,则其最小覆盖圆是以三角形最长边(直角或钝角所对的边)为直径的圆. ·················································································································· 8分 (3)此中转站应建在△EFH的外接圆圆心处(线段EF的垂直平分线与线段EH的垂直平分线的交点处). ·····························································

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