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26.解:(1)(0,-3),b=-
9,c=-3. ··················································· 3分 439(2)由(1),得y=x2-x-3,它与x轴交于A,B两点,得B(4,0).
44y ∴OB=4,又∵OC=3,∴BC=5.
QH由题意,得△BHP∽△BOC,
AOBx∵OC∶OB∶BC=3∶4∶5, P∴HP∶HB∶BP=3∶4∶5, ∵PB=5t,∴HB=4t,HP=3t. C∴OH=OB-HB=4-4t.
3由y=x-3与x轴交于点Q,得Q(4t,0).
4t∴OQ=4t. ·············································································· 4分 ①当H在Q、B之间时, QH=OH-OQ
=(4-4t)-4t=4-8t. ······················································· 5分 ②当H在O、Q之间时, QH=OQ-OH
=4t-(4-4t)=8t-4. ······················································· 6分 综合①,②得QH=|4-8t|; ······················································ 6分 (3)存在t的值,使以P、H、Q为顶点的三角形与△COQ相似. ················ 7分
①当H在Q、B之间时,QH=4-8t,
4?8t3t若△QHP∽△COQ,则QH∶CO=HP∶OQ,得=,
34t7∴t=. ··············································································· 7分
323t4?8t若△PHQ∽△COQ,则PH∶CO=HQ∶OQ,得=,
4t3即t2+2t-1=0.
∴t1=2-1,t2=-2-1(舍去). ········································· 8分 ②当H在O、Q之间时,QH=8t-4.
8t?43t若△QHP∽△COQ,则QH∶CO=HP∶OQ,得=,
34t25∴t=. ··············································································· 9分
323t8t?4若△PHQ∽△COQ,则PH∶CO=HQ∶OQ,得=,
4t3即t2-2t+1=0.
∴t1=t2=1(舍去). ······························································ 10分
725综上所述,存在t的值,t1=2-1,t2=,t3=. ···················· 10分
3232附加题:解:(1)8; ···················································································· 5分
(2)2. ···················································································· 10分
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