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24.(1)证明:∵AC切⊙O于点A,
∴∠BAC=90°. ········································································· 1 连接AD.
∵点E是BD的中点,
CDE∴∠BAE=∠DAE. F∵AB是⊙O的直径, ∴∠ADB=90°. BAO∵∠CAD+∠DAB=∠DAB+∠B=90°, ∴∠CAD=∠B.
∵∠CAD+∠DAE =∠B+∠BAE, ∴∠CAF=∠CFA. ···································································· 2 ∴AC=CF. ············································································· 3
(2)解:∵AB=4,AC=3,
∴BC=5. ················································································ 4 ∵AC=CF=3, ∴BF=2.
∵cosB?∴BD=
BDAB4??, ABBC516. ············································································· 5 5126∴AD=,DF=.
551∴tan∠BAE= tan∠DAE = ························································· 6
225.(1)3.0; ····························································································· 1
(2)如图; ··························································································· 3
(3)1.2或1.6或3.0. ············································································· 6
26.(1)m; ······························································································· 1
(2)∵y?x2?2mx?m2?3??x?m??3,
∴抛物线顶点坐标为(m,-3). ························································ 2
∵抛物线经过点A,B时,且AB∥x轴, ∴抛物线对称轴为x=m=2. ······························································· 3
∴抛物线的表达式为y?x?4x?1; ················································· 4 (3)0?m?1. ···················································································· 6
2227.(1)∠BCD=120°-α. ············································································· 1 (2)解:
方法一:延长BA使AE=BC,连接DE. ······ 2
D 由(1)知△ADC是等边三角形,
∴AD=CD.
∵∠DAB+∠DCB=∠DAB+∠DAE=180°, ∴∠DAB=∠DAE.
C∴△ADE≌△CDB. ···················· 3
P∴BD=BE.
∴BD=AB+BC. ·························· 4
BEA方法二:延长AB使AF=BC,连接CF. ······ 2
∠BDC=∠ADE. ∵∠ABC=120°,
D∴∠CBF=60°.
∴△BCF是等边三角形. ∴BC=CF.
∵∠DCA=∠BCF=60°,
∴∠DCA+∠ACB=∠BCF+∠ACB. CP即∠DCB=∠ACF. ∵CA=CD,
BAF∴△ACF≌△DCB.····················· 3
∴BD=AF.
∴BD=AB+BC. ·························· 4 (3)AC,BD的数量关系是:AC?3BD; ········································· 5 2位置关系是:AC⊥BD于点P. ······································· 6
28.(1)22; ·························································································· 1
(2)22?r?4; ················································································ 3 (3)?25?2?t??5?2或6
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