西工大C语言POJ习题答案

i++; }

for(;i>0;i--){ if(a[j]==a[i-1]){ j++;

continue;} else {k=0; break;} }

if(k==1)

printf(\ else

printf(\}

6.

#include int main() {

double a,c; scanf(\ switch((int)a/10) {

case 0:c=a*0.1;break;

case 1:c=(a-10)*0.075+10*0.1;break; case 2:

case 3:c=(a-20)*0.05+10*0.075+10*0.1;break;

case 4:

case 5:c=(a-40)*0.03+20*0.05+10*0.075+10*0.1;break; case 6: case 7: case 8:

case 9:c=(a-60)*0.015+20*0.03+20*0.05+10*0.075+10*0.1;break;

default:c=(a-100)*0.01+40*0.015+20*0.03+20*0.05+10*0.075+10*0.1; }

printf(\ return 0; } 7.

#include int main() {

double a,b,c; scanf(\ c=(int)a; if(a>c)a=c+1; if(a>15)

b=(a-15)*2.1+7+13*1.5; else { if(a>2)

b=(a-2)*1.5+7; else b=7; }

printf(\