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设G(0,b), 则PG?25,
O E C 图2
x 同(i)可得b=9, 则G(0,9) . ······················································································· (4分) (iii)当Q为直角顶点时, 同(ii)可得G(0,9) .
综上所述,符合条件的点G有两个,分别是G1(0,4),G2(0,9). ················· (5分)
y y Q G G P Q D P O E C 图3 x O E C 图4 x
数学试题 第13页(共13页)
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