最新人教版小学四年级数学下册第六单元课堂达标题

choose the correct meaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: ... ... 一面…… ... 1, to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer languagplenary, and subject: application problem (1)--simple application problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning--through examines the, find known conditions and by seeking problem 2, and analysis number relationship--analysis known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation--lists formula, is out subdivisions 4, and test, and wrote answer--check, and checking, and wrote answers typical application problem 13, and subject: application problem (3)--column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivalent relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation formula, 3, and according to problem in the of focus described sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number4.6.1 小数的加减法（1）

班级 姓名

课堂达标

1.计算下面各题并验算。

6.07＋4.89= 7.2-0.8= 15.62－7.46=

2.在○里填上“＜”、“＞”或“＝”。

19.7－12.5○4.92＋0.65 7.24＋3.06○8.52－0.52 10－5.88○7.78－1.5 26.52＋3.48○19.9＋10.1

3.

（2）哪一年比上一年增加得最多？增加了多少？ 【学习评价】

自评

师评 choose the correct meaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: ... ... 一面…… ... 1, to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer languagplenary, and subject: application problem (1)--simple application problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning--through examines the, find known conditions and by seeking problem 2, and analysis number relationship--analysis known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation--lists formula, is out subdivisions 4, and test, and wrote answer--check, and checking, and wrote answers typical application problem 13, and subject: application problem (3)--column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivalent relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation formula, 3, and according to problem in the of focus described sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number4.6.2 小数的加减法（2）

班级 姓名

课堂达标 1.口算。

2.5+0.9＝ 7.8+1.6＝ 0.39+0.15＝ 1.2-0.5＝ 4.7-2.8＝ 3-1.4＝ 2.计算下面各题并验算。

3.64+0.48＝ 21.56+6.74＝ 7.85+9.19＝

8.24-3.56＝ 41.2-15.6＝ 50-37.5＝

３．

知识拓展。

小糊涂计算6.5＋1.3时错把1.3看成了13计算，正确的计算结果和错误的计算结果相差多少？

choose the correct meaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: ... ... 一面…… ... 1, to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer languagplenary, and subject: application problem (1)--simple application problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning--through examines the, find known conditions and by seeking problem 2, and analysis number relationship--analysis known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation--lists formula, is out subdivisions 4, and test, and wrote answer--check, and checking, and wrote answers typical application problem 13, and subject: application problem (3)--column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivalent relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation formula, 3, and according to problem in the of focus described sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number4.6.3 小数加减法的练习课

班级 姓名

一、基本练习

1.口算下列各题。

0.7＋0.8＝ 4.6－0.5＝ 0.65－0.45 ＝ 2.2＋1.8 ＝ 1－0.2 ＝ 0.37＋0.13＝ 6.6＋0.4 ＝ 3.6－1.6 ＝ 2.笔算下面各题，并验算。

8.02 ＋0.4 ＝ 6 8.5－35.05 ＝ 36－15.12 ＝

二、提高练习

3. 可以怎样买？需要付多少钱？

4.用小数计算下面各题。

先想一想题中的数量关系，再列式解答。要写完整哟！ 三、课堂达标

1.直接写得数

3.5＋2.4＝ 4.2－2.2＝ 4.65－2.34 ＝ 2.5＋1.5 ＝

choose the correct meaning; (4) to correct the typos; (5) so the child write words (ABAB, and AABB); (6) in accordance with written words; (7) the complete word, and explain the meaning of the word; (8) collocation; (9) make sentences with the word; (10) the written language as required. (C) the main sentence types (1) complete sentences; (2) write down the meaning of a sentence or expression of thoughts and feelings; (3) write sentences as required; (4) finish malalignment of the sentence; (5) modified sentences. 2, knowledge classification (1) the common conjunctions coordinate: ... ... 一面…… ... 1, to examine the topic, identify problems associated with two 2, analysis, alternative question two is in direct proportion to the amount of the associated relationship is inversely proportional relationship. 3, and set unknown, column proportion type 4, and solutions proportion type 5, and test, wrote answer languagplenary, and subject: application problem (1)--simple application problem and composite application problem review content simple application problem composite application problem answers application problem of general steps 1, and figure out meaning--through examines the, find known conditions and by seeking problem 2, and analysis number relationship--analysis known conditions Zhijian, and conditions and problem Zhijian of relationship, determine problem-solving method and problem-solving steps. 3, and column type calculation--lists formula, is out subdivisions 4, and test, and wrote answer--check, and checking, and wrote answers typical application problem 13, and subject: application problem (3)--column equation solutions application problem review content overview problem-solving steps 1, and figure out meaning, find by seeking of unknown and x said 2, and according to meaning find equivalent relationship, lists Equation 3, and solutions equation 4, and test, and wrote answers according to meaning find equivalent relationship of common method 1 , And according to common of number relationship type, established equivalent relationship 2, and according to has learn had of calculation formula, 3, and according to problem in the of focus described sentence from overall Shang determine basic of equivalent relationship 4, and using segment figure, and list method, method analysis number10－0.2 ＝ 0.17＋0.13＝ 5.6＋0.4 ＝ 3.72－1.12 ＝ 2.判断，对的打“√”，错的打“×”。

（1）3.7＋3＝4 （ ） （2）10.1－1＝10 （ ） （3）4.07米＋4厘米7分米＝8.77米 （ ）

（4）4千米300米－2.05千米＝2.25千米 （ ） 3.用竖式计算，并且验算。

5.4 ＋3.24＝ 4.6－2.82＝ 四、知识拓展。

一些女子田径项目的中国记奶和世界记录如下表。 【学习评价】 自评

师评