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设A,B对应的参数为t1,t2,由题意得t1?2t2即t1?2t2或t1??2t2,
?t1?2t2?1t?2t当1时,,解得, a?t?t?22?21236?tt?2?1?4a??12?t1??2t2?9当t1??2t2时,?t1?t2?22解得a?,
4?tt?2?1?4a??12综上:a?19或. 36423.考点:绝对值不等式
解:(1)当m??1时,f?x??x?1?2x?1, ①x?1时,f?x??3x?2?2,解得1?x?②当
4; 311?x?1时,f?x??x?2,解得?x?1; 2211③当x?时,f?x??2?3x?2,解得0?x?;
22综合①②③可知,原不等式的解集为?x|0?x???4??. 3??3???(2)由题意可知f?x??2x?1在?,2?上恒成立,当x??,2?时,
44?3???f?x??x?m?2x?1?x?m?2x?1?2x?1?2x?1,从而可得x?m?2,即
?2?x?m?2??2?x?m?2?x,且??2?x?max??
11?11?,?2?x?min?0,因此m???,0?. 4?4?
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