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吉林化工学院化工原理课程设计?
② 进料液相平均表面张力的计算 由tF=58℃查手册得: ?A?26.756mN/m; ?B?22.286mN/m;
?LmF?0.34?26.756?(1?0.34)?22.286?23.806mN/m;
③ 塔釜液相平均表面张力的计算 由tW=74.03℃查手册得: ?A?24.461mN/m; ?B?20.376mN/m
?LmW?0.045?24.461?(1?0.045)?20.376?20.560mN/m; 精馏段液相平均表面张力为:
?m(精)?(28.205?23.806)2?26.006mN/m
提馏段液相平均表面张力为:
?m(提)?(23.806?20.560)2?22.183mN/m
3.2精馏塔气液负荷计算
精馏段:V=(R+1) D=(3.48?1)?27.69?124.05kmol/h
Vs?VMVm(精)3600??124.05?90.29?0.87m3/s
Vm(精)3600?3.59 L=RD= 3.48?27.69?96.36kmol/h L(精)s?LMLm3600??96.36?102.443Lm(精)3600?1343.73?0.00204m/s
Lh=3600?0.00204=7.34m3/h
提馏段:V'?V?(1-q)F?124.05?(1?0.95)?86.34?119.73kmol;
' V'提)s(提)?VMVm(3600??119.73?126.023Vm(提)3600?5.26?0.80m/s;
L'=L+qF=96.36+0.95?86.34=178.38kmol/h; ' L'LMLm(提)s?3600??178.38?132.493Lm(提)3600?1463.35?0.0045m/s;
L'?3600?0.0045?16.20m3h/h;
3.3塔和塔板的主要工艺尺寸的计算
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则:
吉林化工学院化工原理课程设计?
3.3.1 塔径的计算
塔径D 参考下表 初选板间距HT=0.40m,取板上液层高度HL=0.07m 故: ①精馏段:
HT-hL=0.40-0.07=0.33m
0.002041343.732()()?()()?0.0454Vs?V0.873.592Ls?L11 查图表
C20=0.065;依公式 C?C20(?20)0.2?0.065(26.00620)0.2?0.0685;
umax?C?L??v?v?0.0685?1343.73?3.593.59?1.323m/s
取安全系数为0.7,则:
u=0.7?umax=0.7?1.323=0.926m/s
4Vs4?0.87 故:D???u???0.9264Vs?1.094m;
按标准,塔径圆整为1.2m,
则空塔气速为u? 塔的横截面积AT? ②提馏段: (LsV's'?D?42?24?0.87D???1.2?242?0.770m/s
21.2?1.131m
)(??'L'V0.00451463.352)?()()?0.0938;查图
0.805.26211C20=0.062;依公式:C?C20(?20)0.2?22.183??0.062????20?0.2?0.0633;
umax?C?'L??'v?v?0.06331463.35?5.265.26?1.05m/s
取安全系数为0.70,
u?0.7?umax?0.7?1.05?0.735m/s;
'D?'4Vs?u'?4?0.80??0.735?1.178m;
为了使得整体的美观及加工工艺的简单易化,在提馏段与精馏段的塔径相差不大的情况下选择相同的尺寸; 故:D'取1.2m
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吉林化工学院化工原理课程设计?
塔的横截面积:A'T?空塔气速为u'?4Vs?4?D'2??421.2?1.131m ?0.708m/s
224?0.80?D2??1.2板间距取0.4m合适
3.3.2溢流装置
采用单溢流、弓形降液管、平形受液盘及平形溢流堰,不设进流堰。各计算如下:
①精馏段:
1、溢流堰长 lw为0.7D,即:lw?0.7?1.2?0.84m;
2、出口堰高 hw hw=hL-how 由lw/D=0.84/1.2=0.7, Lhl2.5w?7.340.842.5?11.35m2查手册知:
3E为1.02 依下式得堰上液高度:how?L??E?h?1000?lw?2.84?7.34???1.02??1000?0.84?2.8423?0.012m
故:hw?hL-how?0.07?0.012?0.058m
3、降液管宽度Wd与降液管面积Af 有lw/D=0.7查手册得Wd/D?0.14,Af/AT?0.08
故:Wd=0.14D=0.14 ?1.2=0.168m
Af?0.08AfHTLs?4?D?0.08?2?4?1.2?0.0905m
22??0.0905?0.40.00204?17.75s??5s,符合要求?
4、降液管底隙高度h0
取液体通过降液管底隙的流速u0=0.1m/s 依式计算降液管底隙高度h0, 即:h0? ②提馏段:
Lslwu0?0.002040.84?0.1?0.024m
1、堰长l'w为0.7D',即:l'w'2、高hw h'w=hL-h'ow ;
?0.7?1.2?0.84m;
由 l'w/D=0.84/1.2=0.7,Lhl'2.5w?16.20.842.5?25.05m查手册知
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吉林化工学院化工原理课程设计?
E为1.03依下式得堰上液高度:
2how'?L??E?'h?1000?lw?2.843?16.2???1.03??1000?0.84?2.8423?0.025mhw?0.07?0.025?0.045m。
‘3、管宽度W‘d与降液管面积A f’‘’‘’有‘lw/D=0.7查手册得Wd/D?0.14,Af/AT?0.08
故:W‘d=0.14D=0.14 ?1.2=0.168m
A‘f?0.08AfHTLs?4?D'?0.08?0.0905?0.40.00452?4?1.2?0.0905m
22???8.04s??5s,符合要求?降液管底隙高度h'0
取液体通过降液管底隙的流速u0=0.1m/s 依式计算降液管底隙高度h'0 :即 h0?'Lslwu0''?0.00450.84?0.1?0.053m
3.3.3塔板布置
1、取边缘区宽度Wc=0.035m ,安定区宽度Ws=0.065m
①精馏段:依下式计算开孔区面积
?222?1 A??2?xR?x?Rsin?? 180R???x其中x? R?故:
D2D2??Wd?Ws???Wc?1.221.22??0.168?0.065??0.367m
?0.035?0.565m
?222?1 A??2?0.565sin?0.3670.565?0.367?? 1800.565???0.766m2?0.367
②提馏段:依下式计算开孔区面积
A?'?'?2?x?R?x'2'2??180Rsin'2?1'x? '?R? - 16 -
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