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(3)设P(?1,t),又B(?3,0),C(0,3),
②BC2?18,PB2?(?1?3)2?t2?4?t2,PC2?(?1)2?(t?3)2?t2?6t?10,
②若点B为直角顶点,则BC2?PB2?PC2即:18?4?t2?t2?6t?10解之得:t??2, ②若点C为直角顶点,则BC2?PC2?PB2即:18?t2?6t?10?4?t2解之得:t?4, ②若点P为直角顶点,则PB2?PC2?BC2即:4?t2?t2?6t?10?18解之得: t1?3?173?17,t2?. ................................................................................................4分 223?173?17)或(?1,). 22综上所述P的坐标为(?1,?2)或(?1,4)或(?1,
25. 解:点O作ON//BC交AM于点N,.............................................................................1分
ONAO1??..................................................................................1分 BMAB2ONON1点M为弦BC的中点??..............................................................................1分
CMBM2OE:CE?1:2......................................................................................................................1分
AB是圆O的直径,
(2)点M为弦BC的中点OM?BC..............................................................................1分
AM?OC于点E,?OME??MCE,△OME②△MCE...........................................1分
ME2?OE?CE 设OE?x,则CE?2x,ME?2x...............................................1分
在直角△MCE中,CM?6x, sin?ECM?sin?ABC?3 33.....................................................1分 3过点D作DL?BO于点L,AB?10,AB:BC?5:4,BC?8, ……………1分
5447设BD?x,则CD?8?x,BL?DL?x,CH?(8?x),OH?CO?CH?x?
855547x?OHFOy5?,5....................................................................................1分 ?55LDFLxy?5?x88
20x?3577 (其中?x?)...............................................................................1+1分 742以O为圆心,OF为半径的圆经过D y?5OC垂直平分DF,FO?OL,y?5?x.....................................................................1分
8
20x?355112........................................................................................1分 ?5?x, x?7819
此时BD?
9
112. 19
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