µ±Ç°Î»ÖãºÊ×Ò³ > (ÍêÕû°æ)¡¶Êý×ÖÐźŴ¦Àí¡·ÆÚÄ©ÊÔÌâ¿â
?4(1?2z?1?z?2)13.656?2.344z?2?0.2929(1?2z?1?z?2)1?0.1716z1z?1?2
£¨4£©ÓÃÕý×¼ÐͽṹʵÏÖ
x(n)10.2929y(n)21z?1?0.1716
Áù¡¢£¨12·Ö£©ÉèÓÐÒ»FIRÊý×ÖÂ˲¨Æ÷£¬Æäµ¥Î»³å¼¤ÏìÓ¦h(n)Èçͼ1Ëùʾ£º
h(n)21?134120n?2
ͼ1
ÊÔÇ󣺣¨1£©¸ÃϵͳµÄƵÂÊÏìÓ¦H(ej?)£»
£¨2£©Èç¹û¼ÇH(ej?)?H(?)ej?(?)£¬ÆäÖУ¬H(?)Ϊ·ù¶Èº¯Êý£¨¿ÉÒÔÈ¡¸ºÖµ£©£¬?(?)ΪÏàλº¯Êý£¬ÊÔÇóH(?)Óë?(?)£»
£¨3£©ÅжϸÃÏßÐÔÏàλFIRϵͳÊǺÎÖÖÀàÐ͵ÄÊý×ÖÂ˲¨Æ÷£¿£¨µÍͨ¡¢¸ßͨ¡¢´øÍ¨¡¢
´ø×裩£¬ËµÃ÷ÄãµÄÅжÏÒÀ¾Ý¡£
£¨4£©»³ö¸ÃFIRϵͳµÄÏßÐÔÏàλÐÍÍøÂç½á¹¹Á÷ͼ¡£ ½â£º£¨1£©h(n)?(2,1,0,?1,?2)
H(ej?)??h(n)en?04?j?n?h(0)?h(1)e?j??h(2)e?j2??h(3)e?j3??h(4)e?j4?
?2?e?j??e?j3??2e?j4??2(1?e?j4?)?(e?j??e?j3?)
?2e?j2?(e?j2??ej2?)?e?j2?(ej??e?j?)?e?j2?[4jsin(2?)?2jsin(?)]
£¨2£©H(e)?ej??j2?ej?2[4sin(2?)?2sin(?)]?j(?2?)e2[4sin(2?)??2sin(?)]
H(?)?4sin(2?)?2sin(?)£¬ ?(?)??2?2?
£¨3£©H(2???)?4sin[2(2???)]?2sin(2???)??4sin(2?)?2sin(?)??H(?)
¹Ê µ±??0ʱ£¬ÓÐH(2?)??H(0)?H(0)£¬¼´H(?)¹ØÓÚ0µãÆæ¶Ô³Æ£¬H(0)?0£»
µ±???ʱ£¬ÓÐH(?)??H(?))£¬¼´H(?)¹ØÓÚ?µãÆæ¶Ô³Æ£¬H(?)?0
45
ÉÏÊöÌõ¼þ˵Ã÷£¬¸ÃÂ˲¨Æ÷Ϊһ¸öÏßÐÔÏàλ´øÍ¨Â˲¨Æ÷¡£ £¨4£©ÏßÐÔÏàλ½á¹¹Á÷ͼ
x(n)z?1z?1z?1h(0)h(1)z?1h(2)y(n)
°Ë¡¢£¨15·Ö£©¼ò´ðÌâ
£¨1£© ÊÔд³öË«ÏßÐԱ任·¨Éè¼ÆIIRÊý×Ö¸ßͨÂ˲¨Æ÷µÄÖ÷Òª²½Öè¡£
£¨2£© ¼òÊöÀûÓô°º¯ÊýÀ´Éè¼ÆFIRÂ˲¨Æ÷ʱ£¬¶ÔÀíÏëµÍͨÂ˲¨Æ÷¼Ó¾ØÐδ°´¦Àíºó
µÄÓ°Ï졣ΪÁ˸ÄÉÆFIRÂ˲¨Æ÷µÄÐÔÄÜ£¬¾¡¿ÉÄܵÄÒªÇó´°º¯ÊýÂú×ãÄÄÁ½¸öÌõ¼þ£¿ ½â£º£¨1£©1£©½«Êý×Ö¸ßͨÂ˲¨Æ÷µÄƵÂÊÖ¸±êת»»ÎªÄ£Äâ¸ßͨÂ˲¨Æ÷µÄƵÂÊÖ¸±ê(Æä
Öн«¸ßͨ½ØÖ¹ÆµÂÊͨ¹ýÔ¤»ûת»»ÎªÄ£Äâ¸ßͨÂ˲¨Æ÷µÄ½ØÖ¹ÆµÂÊ)
2£©½«Ä£Äâ¸ßͨÂ˲¨Æ÷¼¼ÊõÖ¸±êת»»ÎªÄ£ÄâµÍͨÂ˲¨Æ÷¼¼ÊõÖ¸±ê 3£©Éè¼ÆÄ£ÄâµÍͨÔÐÍÂ˲¨Æ÷
4£©½«Ä£ÄâµÍͨÔÐÍÂ˲¨Æ÷ͨ¹ýË«ÏßÐÔÓ³ÉäΪÊý×ÖµÍͨÔÐÍÂ˲¨Æ÷ 5£©½«Êý×ÖµÍͨÔÐÍÂ˲¨Æ÷ͨ¹ýƵÓò±ä»»ÎªÊý×Ö¸ßͨÂ˲¨Æ÷ £¨2£©ÀíÏëµÍͨÂ˲¨Æ÷¼Ó´°ºóµÄÓ°ÏìÓÐ3µã£º
1£©ÀíÏë·ùÆµÌØÐԵ͏ֱµÄ±ßÑØ±»¼Ó¿í£¬ÐγÉÒ»¸ö¹ý¶É´ø£¬¹ý¶É´øµÄ´ø¿íÈ¡¾öÓÚ´°º¯ÊýƵÏìµÄÖ÷°ê¿í¶È¡£
2£©ÔÚ¹ý¶É´øµÄÁ½²à¸½½ü²úÉúÆð·üµÄ¼ç·åºÍÎÆ²¨£¬ËüÊÇÓÉ´°º¯ÊýƵÏìµÄÅÔ°êÒýÆðµÄ£¬ÅÔ°êÏà¶ÔÖµÔ½´óÆð·ü¾ÍԽǿ¡£
3£©Ôö¼Ó½ØÈ¡³¤¶ÈN£¬½«ËõС´°º¯ÊýµÄÖ÷°ê¿í¶È£¬µ«È´²»ÄܼõСÅÔ°êÏà¶ÔÖµ¡£Ö»ÄܼõС¹ý¶É´ø´ø¿í£¬¶ø²»ÄܸÄÉÆÂ˲¨Æ÷ͨ´øÄ򵀮½ÎÈÐÔºÍ×è´øÖеÄË¥¼õ¡£
ΪÁ˸ÄÉÆÂ˲¨Æ÷µÄÐÔÄÜ£¬¾¡¿ÉÄÜÒªÇó´°º¯ÊýÂú×㣺
1£©Ö÷°ê¿í¶ÈÕ£¬ÒÔ»ñµÃ½Ï¶¸µÄ¹ý¶É´ø
2£©ÅÔ°êÏà¶ÔÖµ¾¡¿ÉÄÜС£¬ÒÔ¸ÄÉÆÍ¨´øµÄƽÎȶȺÍÔö´ó×è´øÖеÄË¥¼õ¡£ Ò»¡¢Ìî¿ÕÌ⣨ÿ¿Õ1·Ö, ¹²10·Ö£©
1£®ÐòÁÐx(n)?sin(3?n/5)µÄÖÜÆÚΪ ¡£
2£®ÏßÐÔʱ²»±äϵͳµÄÐÔÖÊÓÐ ÂÉ¡¢ ÂÉ¡¢ ÂÉ¡£ 3£®¶Ôx(n)?R4(n)µÄZ±ä»»Îª £¬ÆäÊÕÁ²ÓòΪ ¡£
4£®³éÑùÐòÁеÄZ±ä»»ÓëÀëÉ¢¸µÀïÒ¶±ä»»DFTµÄ¹ØÏµÎª ¡£ 5£®ÐòÁÐx(n)=(1£¬-2£¬0£¬3£»n=0£¬1£¬2£¬3), Ô²ÖÜ×óÒÆ2λµÃµ½µÄÐòÁÐΪ ¡£ 6£®ÉèLTIϵͳÊäÈëΪx(n) £¬ÏµÍ³µ¥Î»ÐòÁÐÏìӦΪh(n)£¬ÔòϵͳÁã״̬Êä³öy(n)= ¡£
7£®Òò¹ûÐòÁÐx(n)£¬ÔÚZ¡ú¡Þʱ£¬X(Z)= ¡£ ¶þ¡¢µ¥ÏîÑ¡ÔñÌ⣨ÿÌâ2·Ö, ¹²20·Ö£© 1£®¦Ä(n)µÄZ±ä»»ÊÇ £¨ £©A.1 B.¦Ä(¦Ø) C.2¦Ð¦Ä(¦Ø) D.2
46
¦Ð
2£®ÐòÁÐx1£¨n£©µÄ³¤¶ÈΪ4£¬ÐòÁÐx2£¨n£©µÄ³¤¶ÈΪ3£¬ÔòËüÃÇÏßÐÔ¾í»ýµÄ³¤¶ÈÊÇ £¨ £©A. 3 B. 4 C. 6 D. 7 3£®LTIϵͳ£¬ÊäÈëx£¨n£©Ê±£¬Êä³ö£¨yn£©£»ÊäÈëΪ3x£¨n-2£©£¬Êä³öΪ £¨ £© A. y£¨n-2£© B.3y£¨n-2£© C.3y£¨n£© D.y£¨n£©
4£®ÏÂÃæÃèÊöÖÐ×îÊʺÏÀëÉ¢¸µÁ¢Ò¶±ä»»DFTµÄÊÇ £¨ £©
A.ʱÓòΪÀëÉ¢ÐòÁУ¬ÆµÓòΪÁ¬ÐøÐźÅ
B.ʱÓòΪÀëÉ¢ÖÜÆÚÐòÁУ¬ÆµÓòҲΪÀëÉ¢ÖÜÆÚÐòÁÐ C.ʱÓòΪÀëÉ¢ÎÞÏÞ³¤ÐòÁУ¬ÆµÓòΪÁ¬ÐøÖÜÆÚÐźÅ
D.ʱÓòΪÀëÉ¢ÓÐÏÞ³¤ÐòÁУ¬ÆµÓòҲΪÀëÉ¢ÓÐÏÞ³¤ÐòÁÐ
5£®ÈôһģÄâÐźÅΪ´øÏÞ£¬ÇÒ¶ÔÆä³éÑùÂú×ãÄοüË¹ÌØÌõ¼þ£¬ÀíÏëÌõ¼þϽ«³éÑùÐźÅͨ¹ý ¼´¿ÉÍêÈ«²»Ê§Õæ»Ö¸´ÔÐźŠ£¨ £©A.ÀíÏëµÍͨÂ˲¨Æ÷ B.ÀíÏë¸ßͨÂ˲¨Æ÷ C.ÀíÏë´øÍ¨Â˲¨Æ÷ D.ÀíÏë´ø×èÂ˲¨Æ÷ 6£®ÏÂÁÐÄÄÒ»¸öϵͳÊÇÒò¹ûϵͳ £¨ £©A.y(n)=x (n+2) B. y(n)= cos(n+1)x (n) C. y(n)=x (2n) D.y(n)=x (- n)
7£®Ò»¸öÏßÐÔʱ²»±äÀëɢϵͳÎȶ¨µÄ³äÒªÌõ¼þÊÇÆäϵͳº¯ÊýµÄÊÕÁ²Óò°üÀ¨ £¨ £©
A. ʵÖá B.Ôµã C.µ¥Î»Ô² D.ÐéÖá
8£®ÒÑÖªÐòÁÐZ±ä»»µÄÊÕÁ²ÓòΪ£üz£ü>2£¬Ôò¸ÃÐòÁÐΪ £¨ £©A.ÓÐÏÞ³¤ÐòÁÐ B.ÎÞÏÞ³¤ÐòÁÐ C.·´Òò¹ûÐòÁÐ D.Òò¹ûÐòÁÐ
9£®ÈôÐòÁеij¤¶ÈΪM£¬ÒªÄܹ»ÓÉÆµÓò³éÑùÐźÅX(k)»Ö¸´ÔÐòÁУ¬¶ø²»·¢ÉúʱÓò»ìµþÏÖÏó£¬ÔòƵÓò³éÑùµãÊýNÐèÂú×ãµÄÌõ¼þÊÇ ( )
A.N¡ÝM B.N¡ÜM C.N¡Ü2M D.N¡Ý2M
10£®ÉèÒò¹ûÎȶ¨µÄLTIϵͳµÄµ¥Î»³éÑùÏìÓ¦h(n)£¬ÔÚn<0ʱ£¬h(n)= ( )
A.0 B.¡Þ C. -¡Þ D.1 Èý¡¢ÅжÏÌ⣨ÿÌâ1·Ö, ¹²10·Ö£©
1£®ÐòÁеĸµÁ¢Ò¶±ä»»ÊÇÆµÂʦصÄÖÜÆÚº¯Êý£¬ÖÜÆÚÊÇ2¦Ð¡£ £¨ £©
2£®x(n)= sin£¨¦Ø0n)Ëù´ú±íµÄÐòÁв»Ò»¶¨ÊÇÖÜÆÚµÄ¡£ £¨ £©
3£®FIRÀëɢϵͳµÄϵͳº¯ÊýÊÇzµÄ¶àÏîʽÐÎʽ¡£ £¨ £©
4£®y(n)=cos[x(n)]Ëù´ú±íµÄϵͳÊÇ·ÇÏßÐÔϵͳ¡£ £¨ £©
5£®FIRÂ˲¨Æ÷½ÏIIRÂ˲¨Æ÷µÄ×î´óÓŵãÊÇ¿ÉÒÔ·½±ãµØÊµÏÖÏßÐÔÏàλ¡£ £¨ £©
6£®ÓÃË«ÏßÐԱ任·¨Éè¼ÆIIRÂ˲¨Æ÷£¬Ä£Äâ½ÇƵת»»ÎªÊý×Ö½ÇÆµÊÇÏßÐÔת»»¡£ £¨ £©
7£®¶ÔÕýÏÒÐźŽøÐвÉÑùµÃµ½µÄÕýÏÒÐòÁÐÒ»¶¨ÊÇÖÜÆÚÐòÁС£
47
£¨ £©
8£®³£ÏµÊý²î·Ö·½³Ì±íʾµÄϵͳΪÏßÐÔÒÆ²»±äϵͳ¡£ £¨ £© 9£®FIRÀëɢϵͳ¶¼¾ßÓÐÑϸñµÄÏßÐÔÏàλ¡£ £¨ £©
10£®ÔÚʱÓò¶ÔÁ¬ÐøÐźŽøÐгéÑù£¬ÔÚÆµÓòÖУ¬ËùµÃƵÆ×ÊÇÔÐÅºÅÆµÆ×µÄÖÜÆÚÑÓÍØ¡£ £¨ £©
ËÄ¡¢¼ò´ðÌâ £¨Ã¿Ìâ5·Ö£¬¹²20·Ö£©
1£®ÓÃDFT¶ÔÁ¬ÐøÐźŽøÐÐÆ×·ÖÎöµÄÎó²îÎÊÌâÓÐÄÄЩ£¿
2£®»³öÄ£ÄâÐźÅÊý×Ö»¯´¦Àí¿òͼ£¬²¢¼òҪ˵Ã÷¿òͼÖÐÿһ²¿·ÖµÄ¹¦ÄÜ×÷Óᣠ3£®¼òÊöÓÃË«ÏßÐÔ·¨Éè¼ÆIIRÊý×ÖµÍͨÂ˲¨Æ÷Éè¼ÆµÄ²½Öè¡£ 4£®8µãÐòÁеݴʱ¼ä³éÈ¡µÄ£¨DIT£©»ù-2 FFTÈçºÎ±íʾ£¿ ¼ÆËãÌâ £¨¹²40·Ö£©
z2,1£®ÒÑÖªX(z)?(z?1)(z?2)z?2£¬Çóx(n)¡££¨6·Ö£©
2£®Ð´³ö²î·Ö·½³Ì±íʾϵͳµÄÖ±½ÓÐͺͼ¶ÁªÐͽṹ¡££¨8·Ö£© £®£®
311y(n?1)?y(n?2)?x(n)?x(n?1) 4833£®¼ÆËãÏÂÃæÐòÁеÄNµãDFT¡£
y(n)?£¨1£©x(n)??(n?m)£¨2£©x(n)?ej2?mnN(0?m?N)(0?m?N)£¨4·Ö£© £¨4·Ö£©
4£®ÉèÐòÁÐx(n)={1£¬3£¬2£¬1£»n=0,1,2,3 }£¬ÁíÒ»ÐòÁÐh(n) ={1£¬2£¬1£¬2£»n=0,1,2,3}£¬ £¨1£©ÇóÁ½ÐòÁеÄÏßÐÔ¾í»ý yL(n)£» £¨4·Ö£© £¨2£©ÇóÁ½ÐòÁеÄ6µãÑ»·¾í»ýyC(n)¡£ £¨4·Ö£© £¨3£©ËµÃ÷Ñ»·¾í»ýÄÜ´úÌæÏßÐÔ¾í»ýµÄÌõ¼þ¡££¨2·Ö£© 5£®ÉèϵͳÓÉÏÂÃæ²î·Ö·½³ÌÃèÊö£º
y(n)?y(n?1)?y(n?2)x(n?1)
£¨1£©Çóϵͳº¯ÊýH£¨z£©£»£¨2·Ö£© £¨2£©ÏÞ¶¨ÏµÍ³Îȶ¨£¬Ð´³öH£¨z£©µÄÊÕÁ²Óò£¬²¢Çó³öÆäµ¥Î»Âö³åÏìÓ¦h(n)¡££¨6·Ö£© £®£®
Ò»¡¢Ìî¿ÕÌ⣨±¾Ìâ¹²10¸ö¿Õ£¬Ã¿¿Õ1·Ö£¬¹²10·Ö£©
±¾ÌâÖ÷Òª¿¼²éѧÉú¶Ô»ù±¾ÀíÂÛÕÆÎճ̶ȺͷÖÎöÎÊÌâµÄÄÜÁ¦¡£ ÆÀ·Ö±ê×¼£º
1£®ËùÌî´ð°¸Óë±ê×¼´ð°¸Ïàͬ£¬Ã¿¿Õ¸ø1·Ö£»Ìî´í»ò²»Ìî¸ø0·Ö¡£
2£®ËùÌî´ð°¸ÊÇͬһÎÊÌ⣨¸ÅÄî¡¢ÊõÓµÄ²»Í¬ÃèÊö·½·¨£¬ÊÓΪÕýÈ·£¬¸ø1·Ö¡£ ´ð°¸£º 1.10
2.½»»»ÂÉ£¬½áºÏÂÉ¡¢·ÖÅäÂÉ
1?z?4,3.
1?z?1
z?0
48
¹²·ÖÏí92ƪÏà¹ØÎĵµ