电化学试题

电池反应 H2(p?)?HgO(s)?Hg(l)?H2O(l) (2)

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在298K时，E2(298K) = E2(298K) =925.7mV

?rGm(2)??zE2F??2?(925.7?10?3V)(96480C?mol?1)??178.66kJ?mol?1

??E??rSm(2)??zF?2??2?(96480C?mol?1)(?0.2948?10?3V?K?1)??0.0569kJ?K?1?mol?1??T?p?rHm(2)??rGm(2)?T?rSm(2)?[?178.65?298?(?0.0569)]kJ?mol?1??195.62kJ?mol?1

已知 H2(p?)?1O2(p?)?H2O(l) (3) 2?1 Jmol237.?13k?已知 ?rGm(3)??G?,?l)fm(H2O? ?rHm(3)??H?,?l)fm(H2O?1 Jmol285.?83k又 (3) – (2)得

Hg(l)?1O2(p?)?HgO(s) (4) 2??fGm(HgO)??rGm(4)??rGm(3)??rGm(2)?(?237.13?178.66)kJ?mol?1??58.47kJ?mol?1

??fHm(HgO)??rHm(4)??rHm(3)??rHm(2)?(?285.83?195.62)kJ?mol?1??90.21kJ?mol?1又 (1) + (4)得

12Cu(s)?O2(p?)?Cu2O(s) (5)

2??fGm(Cu2O)??rGm(5)??rGm(1)??rGm(4)

?(?89.11?58.47)kJ?mol?1??147.58kJ?mol?1

??fHm(Cu2O)??rHm(5)??rHm(1)??rHm(4)

?(?97.39?90.21)kJ?mol?1??187.60kJ?mol?1