ǰλãҳ > 工程力学_静力学与材料力学__高等教育出版社_课后答案 - 百度文库
(4) ѡϵBxyгƽ̣ⷽ
?Fx?0: FAx?50?0 F
Ax?50 kN?M3B(F)?0: ?FAy?6??0q?dx?x?FD?3?50?3?0
FAy?25 kN?F3y?0: FAy??0q?dx?FB?FD?0
FB?10 kNԼķͼʾ
4-18 ɸABBCCEɵ֧ܺͻE֧塣12 kNDΪӣߴ4-18ͼ
ʾ̶֧A֧BԼԼBCܵ C 2m 2m 1.5m
B A
D 1.5m
E
W ⣺(1) о壬ͼ(ƽϵ) y C 2m 2m 1.5m A B Fx
Ax FD A y FB 1.5m W E
W
(2) ѡϵAxyгƽ̣ⷽ
?Fx?0: FAx?W?0 FAx?12 kN
?MA(F)?0: FB?4?W??1.5?r??W??2?r??0 FB?10.5 kN
?Fy?0: FAy?FB?W?0 FAy?1.5 kN
(3) оCE()ͼ(ƽϵ)
C
FCB
FDx FD D y W E
W (4) ѡDΪģгƽ̣ⷽ
?MD(F)?0: FCBsin??1.5?W??1.5?r??W?r?0 FCB?15 kN
Լķͼʾ
4-19 ع4-19ͼʾߴ絥λΪmmֱd=200 mm˿бƽڸBE
غW=10 kNƣ̶֧ABԼ
800 300
E A C
D 600 W
⣺(1) о壬ͼB (ƽϵ)
y 800 300 E FAx A C FA y D 600 W W
FBx B x
(2) ѡϵBxyгƽ̣ⷽ
?MB(F)?0: FAx?600?W?1200?0 F
Ax?20 kN?Fx?0: ?FAx?FBx?0 FBx?20 kN
?Fy?0: ?FAy?FBy?W?0
(3) оACDˣͼ(ƽϵ)
FFC Ax A C FDx
FA y FD
D y
(4) ѡDΪģгƽ̣ⷽ
?
MD(F)?0: FAy?800?FC?100?0 F
Ay?1.25 kN(5) FAy뵽ǰƽ̣ⷽ
FBy?FAy?W?11.25 kN
Լķͼʾ
4-20 ABACDE4-20ͼʾDEһFAC˵ĵڡˮƽDEE
һǦFʱABܵAD=DBDF=FEBC=DEиؾơ A F D F E
45oB C ⣺(1) ƽ㽻֪BԼһBC
(2) оDFEˣͼ(ƽϵ)
FF D F 45o E
FDx FD y B (3) ֱѡFBΪģгƽ̣ⷽ
?MF(F)?0: ?F?EF?FDy?DE?0 FDy?F?MB(F)?0: ?F?ED?FDx?DB?0 FDx?2F(4) оADBˣͼ(ƽϵ) y A Fx
Ax FA y D FDx FD y FB B (5) ѡϵAxyгƽ̣ⷽ
?MA(F)?0: F'Dx?AD?FB?AB?0 F
B?F?Fx?0: ?FAx?FB?F'Dx?0 F
Ax?F?Fy?0: ?F'Ay?FDy?0 FAy?F
Լķͼʾ
5-4 һW=1000 NʱֹABCE֧ˮƽϣˮƽABת
ڰһżżΪM象ƽ⡣֪a=3 mb=4 mh=5 mM=2000 NmӵABԼ z E h D A y M b B
x a C⣺(1) оʱ壬ͼ(ռϵ) z E h FAz FA y D F Ax A y FBz M FC b
FB y
B W x a C
(2) ѡϵAxyzгƽ̣ⷽ
?Mz(F)?0: M?FBy?4?0 FBy?500 N
?Mx(F)?0: ?W?a2?F2C?2a?0 FC?707 N?Mby(F)?0: ?FBz?b?W?22?FC?2b?0 FBz?0?Fz?0: FBz?FAz?W?F2C?2?0 FAz?500 N?F?0: F24xAx?FC?2?5?0 FAx?400 N?F2y?0: ?FBy?FAy?FC?2?35?0 FAy?800 NԼķͼʾ
5-5 ڰ뾶Ϊ120 mmijϵFƶƤˮƽABת֪ƤΪ200 N
ɱΪ100 Nߴ5-5ͼʾFĴСԼABԼ(ߴ絥λmm) F 100N 160 200N 20o B
D A C 100 150
100 : (1) о壬ͼ(ռϵ) F 100N 160 200NF 20o B y y B
FA y D A C FBx
z FAx
150 100
100 x (2) ѡϵAxyzгƽ̣ⷽ
?Mz(F)?0: ?Fcos20o?120??200?100??80?0 F?70.9 N
?Mx(F)?0: ?Fsin20o?100??200?100??250?FBy?350?0 FBy?207 N
?My(F)?0: ?Fcos20o?100?FBx?350?0 FBx?19 N
?F?FԼķͼʾ
yx?0: ?FAx?Fcos20o?FBx?0 FAx?47.6 No
Լķͼʾ
?Fz?0: ?FAz?Fsin20o?FBz?0 FAz?1.46 kN
?0: ?FAy?Fsin20?FBy??100?200??0 FAy?68.8 N5-6 ijAB֧УԲֱֵĽԲֱd=17.3 cmѹ=20ڷһż
M=1030 NmżغĦƣתʱFABеԼ(ͼгߴ絥λΪcm)
o
z z A 22 C d D F 20 oB E M y x 20 oE M x F : (1) о壬ͼ(ռϵ)
FAx x FBx 20 oz FB z FA z E M F FAx x z A FA z 22 C FB z B E M y d FBx D F 20 o
(2) ѡϵAxyzгƽ̣ⷽ
?My(F)?0: Fcos20o?d?M?0 2 F?12.67 kNx?M(F)?0: Fsin20o?22?FBz?33.2?0 FBz?2.87 kN
?M(F)?0: Fcos20zo?22?FBx?33.2?0 FBx?7.89 kN
?Fx?0: FAx?Fcos20o?FBx?0 FAx?4.02 kN
92ƪĵ